4 1/2 x 10 3/8 114 x 264 12 4 3/4 x 11 121 x 279 14 5 x 11 1/2 127 x 292 Announcement (Square Flap)If 4 = x 2 then x 2 = 4 If x 3 = 2x 5 then 2x 5 = x 3 If d = rt then rt = d There may be several different ways to apply the addition property above Sometimes one method is better than another, and in some cases, the symmetric property of2x2=8 x3=5 3x2=18 2x10=12 6x2=14 3x=12 4x2=12 9x3=6 12x=5 x8=13 all equations
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5^x-3*3^2x-8=225-View more examples » Access instant learning tools Get immediate feedback and guidance with stepbystep solutions and Wolfram This is the Solution of Question From RD SHARMA book of CLASS 9 CHAPTER NUMBER SYSTEMS This Question is also available in R S AGGARWAL book of CLASS 9 You ca
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Remainder of x^32x^25x7 divided by x3;Expand polynomial (x3)(x^35x2) GCD of x^42x^39x^246x16 with x^48x^325x^246x16;We have to find the value of x provided \\frac{3^{2x 8}}{225} = \frac{5^3}{5^x},\ So, \\frac{3^{2x 8}}{3^2 × 5^2} = \frac{5^3}{5^x}\ By cross multiplication we get `3^(2x8) xx 5^x = 3^2xx5^2 xx5^3` By equating exponents we get `3^(2x8) = 3^2` `2x 8 = 2` `2x= 28` `2x = 10` `x=10/2` `x=5` And `5^x = 5^(32)` `x=32` `x=5`
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Postcards Tent & Place Cards Note Cards Greeting Cards Index Cards View All 17/16" x 33/4" 2" x 31/2" 21/2" x 81/2"No obligation Start today $995 per month (cancel anytime) See detailsThe prime factorization of 18 is 2 x 3 x 3 = 18 The prime factorization of 27 is 3 x 3 x 3 = 27 The occurrences of common prime factors of 18 and 27 are 3 and 3 So the greatest common factor of 18 and 27 is 3 x 3 = 9 Example Find the GCF (, 50, 1) The prime factorization of is 2 x 2 x 5 = The prime factorization of 50 is 2 x 5 x
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4 Follow 3 Lalit Mehra, Meritnation Expert added an answer, on Lalit Mehra answered this 1 5 x – 3 × 3 2x – 8 = 225 ∴ 5 x – 3 × 3 2x – 8 = 25 × 9 ⇒ 5 x – 3 × 3 2x – 8 = 5 2 × 3 2 ∴ x – 3 = 2 ⇒ x = 5Guided, stepbystep explanations to your math solutions Ability to take a photo of your math problem using the app Breakdown of the steps and substeps to each solution Available online 24/7 (even at 3AM) Cancel subscription anytime;, the numerator is 3, and the denominator is 8 A more illustrative example could involve a pie with 8 slices 1 of those 8 slices would constitute the numerator of a fraction, while the total of 8 slices that comprises the whole pie would be the denominator If a person were to eat 3 slices, the remaining fraction of the pie would therefore be
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Simple and best practice solution for x^2=225 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework 2x2=8 x3=5 3x2=18 2x10=12 6x2=14 3x=12 4x2=12 9x3=6 12x=5 x8=13 all equationsIf `5^ (x3) 3^ (2x8) = 225 Watch later Share Copy link Info Shopping Tap to unmute If playback doesn't begin shortly, try restarting your device Up Stepbystep explanation 5^x3*3^2x8=225 5^x3*3^2x8=5^2*3^2 5^x3=5^2 and 3^2x8=3^2 x3=2 and 2x8=2 x=5 and x=28/2 =10/2=5 so x=5 mark as brainliest
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The procedure to use the distributive property calculator is as follows Step 1 Enter an expression of the form a (bc) in the input field Step 2 Now click the button "Submit" to get the simplified expression Step 3 Finally, the simplificationQuotient of x^38x^217x6 with x3;Answer We have, 5x−3 ×32x−8 =225 535x × 32x = 225 5x ×32x =25×9×53 ×38
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5⁄ 8 = 11⁄ 16 = 3⁄ 4 = 1905 13⁄ 16 = 638 7⁄ 8 15 = ⁄16 = 1 = 254 inchescm 1 = 25 11⁄ 4 = 32 11⁄ 2 = 38 13⁄ 4 = 44 2 = 5 21⁄ 4 = 57 21⁄ 2 = 64 23⁄ 4 = 7 3 = 76 31⁄ 4 = 31⁄ 2 = 33⁄ 4 = 95 4 = 102 41⁄ 4 = 108 41⁄ 2 = 114 43⁄ 4 = 12 5 = 127 51⁄ 4 = 133 513^(2x8) * 5^x = 225*125 Cross Multiply the Terms and 5^3 is 5*5*5 is 125 so Now the terms Of RHS Is Equal to 5^5*3^2 so now as Base are same So powers Are same so 5^x=5^5 so x = 5 3^(2x8) = 3^2 so 2x8 = 2 2x = 10 so indeed x = 5 Thank youSNAP is a parallelogram in which ∠ P S O = 5 0 ° and ∠ N S O = 2 5 ° and ∠ A O P = 6 0 ° Find ∠ S N O, ∠ O P A, ∠ S A N and ∠ A N P Medium View solution > two cows are bought, each at the same cost,one was sold at aprofit of 125 and the other at a loss of 8% if the actual difference of the selling prices were rs 144 find
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1) b nominal width minus 3 times the design wall thickness t t design wall thickness h nominal depth minus 3 times the design wall thickness t I moment of inertia of crosssection S elastic section modulus r radius of gyration Z plastic section modulus 2) Note that the cross sectional areas are calculated for sections withY x √ abs round N rand 225 can be written in the form of prime factors as 3 × 3 × 5 × 5 = 3² × 5² So, the equation will be formed which is as follows Comparing the value of 5 with 5 and 3 with 3 , we have, So, also, x = 5 Thus the value of x is 5
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